Factor 6x^3+33x^2-63x completely

6x333x2-63x

#1

factor 6x^3+33x^2-63x completely

Answer:

First factor out the 3x, 3x(2x^2 +11x-21)
You can now factor the quadratic inside the parathesis
Break into groups (2x^2-3x)+(14x-21)
Factor out the common terms
x(2x-3)+7(2x-3)
(2x-3)(x+7)
There it is