Factor 4y^2–12y+5

4y212y5

#1

factor 4y^2–12y+5

Answer:

4y^2-12y+5
Split 12y such that you have a number that is a multiple of 4 (for 4y^2) and 5 (constant)
So
4y^2-2y-10y+5
Factor out
2y(2y-1)-5(2y-1)
2y-1 is common so factor it out
(2y-1)(2y-5)

Case 1: take 4 times 5 = 20, so find divisor of 20, find pair divisor which two divisor add together = -12, so just have 20=(-10)x(-2) and -10+(-2)=-12 then
4y^2 - 12y + 5
4y^2 -10y - 2y + 5
2y(2y - 5) -1(2y - 5)
taking (2y - 5) common
(2y - 5)(2y - 1)
Case 2: use calculator find 2 root of equation