**factor 4y^2–12y+5**

**Answer:**

4y^2-12y+5

Split 12y such that you have a number that is a multiple of 4 (for 4y^2) and 5 (constant)

So

4y^2-2y-10y+5

Factor out

2y(2y-1)-5(2y-1)

2y-1 is common so factor it out

(2y-1)(2y-5)

**Case 1:** take 4 times 5 = 20, so find divisor of 20, find pair divisor which two divisor add together = -12, so just have 20=(-10)x(-2) and -10+(-2)=-12 then

4y^2 - 12y + 5

4y^2 -10y - 2y + 5

2y(2y - 5) -1(2y - 5)

taking (2y - 5) common

(2y - 5)(2y - 1)

**Case 2:** use calculator find 2 root of equation