**f(x)=3/2x**

**find the intervals over which the funtion is increasing decreasing or constant**

**Answer:**

I assume you mean f(x)=3/(2x)

f’(x)=(3/2)(-1(x)^-2)

0=(-3/2)(x^-2)

x=0

when x=0 function constant when x is greater then 0 function decreasing when x is less then 0 function is increasing