Express the given quantity as a single logarithm . 1/3 In(x + 2)3 + 1/2[In x - In(x2 + 3x + 2)2]

single-logarithm
23-12in-x-inx2-3x-22

#1

Express the given quantity as a single logarithm . 1/3 In(x + 2)3 + 1/2[In x - In(x2 + 3x + 2)2]

Answer: