Expand (3x-4)^4 using pascal's triangle

pascals-triangle

#1

expand (3x-4)^4 using pascal’s triangle

Answer:

a^4+4a^3b+6a^2b^2+4ab^3+b^4
a=3x
b=-4

(3x)^4+4(3x)^3(-4)+6(3x)^2(-4)^2+4(3x)(-4)^3+(-4)^4

81x^4 - 432x^3 + 864x^2 - 768x +256