Draw the product for the following reaction between an alkyne and one equivalent of HCl

markonikov-addition

#1

Draw the product for the following reaction between an alkyne and one equivalent of HCl.

image

Concepts and reason
The given question is based on the concept of the Markonikov’s addition. The unsaturated carbon compounds can undergo the process of the addition reaction with the other molecules and can form a new compound.

Fundamentals
The Markonikov’s addition process is the process of the addition reaction helps in the determination of the addition product of the given compounds. The rule of the addition suggests that the addition of the protic acid (HX) to the asymmetric alkenes or alkynes takes place in such a way that the hydrogen is attached to the more hydrogen substituted carbon. The X (halide) from the HX attached to the more alkyl substituted carbon.

Answer:

The alkyne undergoes the process of the addition reaction by breaking one bond out of the three bonds. The breakage of the bond helps in the attachment of the substituents.

Explanation:
The alkenes are the molecules with triple bond. The breakage of the bond of the alkene in the presence of the protic acid take place in the heterolytic manner. This result in the lack of electron on one carbon of the alkyne group and one extra electron on the other carbon.

The protic acid present in the reaction is HCl (hydrochloric acid). The halide group of the HCl, that is image attached to the more substituted carbon and the hydrogen attached to the more hydrogen substituted carbon.

image

Explanation:
The Markonikov’s addition reaction takes place in such a way that the halide group of the HCl, that is image attached to the more alkyl substituted group. The carbon 2 in the above reaction is more alkyl substituted in the given compound. Hence, the reaction result in the formation of the image.