Determine the zeros and the multiplicity of any multiple zeros. y = x² (x+1)²(2x+3)

multiple-zeros

#1

Determine the zeros and the multiplicity of any multiple zeros.

y = x² (x+1)²(2x+3)

Answer:

The zeros are when y is zero. So you can set x equal to 0, -1, and -3/2 (or -1.5) to make y=0. Those are the x-intercepts and the zeros.

The Multiplicity is the degree at which each separate part is. For x=0, the multiplicity is two because the first x that would make y=0 has a power of two.

For the second part, (x+1)², the multiplicity is again the power so it would be two.

For the final part since there is no power we can assume it is a one.

Sorry for the late response. Hope it still helps you.

-Lance