Determine the balanced chemical equation for this reaction. C8H18(g)+O2(g)→CO2(g)+H2O(g)


#1

Determine the balanced chemical equation for this reaction. C8H18(g)+O2(g)→CO2(g)+H2O(g)

Part A:
Enter the coefficients for each compound in order, separated by commas. For example, 1,2,3,4 would indicate one mole of C8H18, two moles of O2, three moles of CO2, and four moles of H2O.

2,25,16,18

Part B:
0.280 mol of octane is allowed to react with 0.630 mol of oxygen. Which is the limiting reactant?
Oxygen

Part C:
How many moles of water are produced in this reaction?
image

Part D:
After the reaction, how much octane is left?

Concepts and reason
Balance the equation by placing appropriate coefficients before the reactant and products. Then write the coefficients that present before the each compound.
Use mole ratio concept to find the limiting reagent. Moles of one substance to moles of another substance in a balanced chemical equation is called mole ratio.
Calculate the number of moles of water by using the moles of the limiting reagent.

Fundamentals
In a balanced chemical equation, number of atoms of each element and total in the reactant side and product side are equal to each other.
A limiting reagent is completely consumed in a chemical reaction.
A conversion factor is used to convert between moles of one substance to moles of another substance.

Answer:

Part A:
The balanced equation is as follows:
image
The coefficients of the each compound in order are 2, 25, 16, and 18.

image

image

Part B:
Calculate number of moles of image by using the moles of each reactant.
image
The reactant oxygen produce less product compared to the reactant octane. So, the limiting reagent is image.

Part B
Limiting reagent is image.

Compare the moles calculated by using the reactants oxygen and octane. Limiting reagent is one that has less number of moles compared with the other reactants in the reaction. The reactant image. less number of moles, hence it will be the limiting reagent.

Part C:
image
image

The reactant for which we calculate moles should be on the top of the conversion factor.
Moles of image should be on the top of the conversion factor. The calculated moles of image is 0.453 mol.

Part D:

Calculate moles of octane reacted by using the following conversion factor.
Conversion factor to get moles of octane from moles of octane is as follows:
image

Part D
Amount of octane left is 0.229mol.

The reactant for which we calculate moles should be on the top of the conversion factor.
Moles of octane should be on the top of the conversion factor. Calculate the amount of octane remained by subtracting the moles of octane consumed from the moles of octane allowed in the reaction.
The calculated mole of octane left in the reaction is 0.229mol.

image