Consider a metal exposed to light of

wavelength 600 nm. The maximum energy of the electron doubles when light of wavelength 400 nm is used. Find the work function in eV.

# Consider a metal exposed to light of wavelength 600 nm

**prasanna**#1

**prasanna**#2

Given, for the first condition,

Wavelength of light, λ = 600

Wavelength of light, λ’ = 400 nm

Also, maximum kinetic energy for the second condition is equal to the twice of the kinetic energy in first condition, then,