$CH_{ 2 }$ = CH is more basic than HC=${{C}^{-}}$ . Explain why?

Since, sp-carbon is more electronegative than {{sp}^{2}}-carbon, therefore, CH={{C}^{-}} is less willing to donate a pair of electrons than H_{ 2 }C=C{{H}^{-}}. In other words, H2C=CH is more basic than HC={{C}^{-}}.