$CH_{ 2 }$ = CH is more basic than HC=${{C}^{-}}$ . Explain why?

cbse
organicchemistry

#1

Since, sp-carbon is more electronegative than ${{sp}^{2}}$-carbon, therefore, CH=${{C}^{-}}$ is less willing to donate a pair of electrons than $H_{ 2 }C$=$C{{H}^{-}}$. In other words, H2C=CH is more basic than HC=${{C}^{-}}$.