Mol. weight of N${{H}*{3}}$ = 14 + 3 = 17 g ${{mol}^{-1}}$
1 mole of N${{H}*{3}}$ = 17g of N${{H}

*{3}}$ has volume = 22.4 L at STP*

=> 34 g of N${{H}{3}}$ = 22.4x34/63 = 44.8 L

=> 34 g of N${{H}

Mol. weight of N${{H}*{3}}$ = 14 + 3 = 17 g ${{mol}^{-1}}$
1 mole of N${{H}*{3}}$ = 17g of N${{H}

=> 34 g of N${{H}