Calculate the volume of 34g of N${{H}_{3}}$ at STP

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conceptsofchemistry

#1

Mol. weight of N${{H}{3}}$ = 14 + 3 = 17 g ${{mol}^{-1}}$
1 mole of N${{H}
{3}}$ = 17g of N${{H}{3}}$ has volume = 22.4 L at STP
=> 34 g of N${{H}
{3}}$ = 22.4x34/63 = 44.8 L