Calculate the total number of electrons present in 1.6 g of methane

cbse
conceptsofchemistry

#1

1.Molar mass of methane = 12 + 4 x 1 = 16g
16 g of methane contains molecules = 6.022 x ${{10}^{23}}$
1.6 g of methane will contain molecules =
6.022 x ${{10}^{23}}$ / (16 g) x (1.6 g)
= 6.022 x ${{10}^{22}}$
2. Number of electrons in 6.022 x ${{10}^{22}}$ molecules of methane.
1 molecule of methane contains electrons = 6 + 4 = 10
6.022 x ${{10}^{22}}$ molecules of methane contain electrons = 6.022 x ${{10}^{22 }}$ x 10 = 6.022 x ${{10}^{23}}$