Calculate the theoretical oxygen demand (ThOD) of 150 ppm glucose?

theoretical-oxygen

#1

Calculate the theoretical oxygen demand (ThOD) of 150 ppm glucose ?

Answer:

C6H12O6 + 6 O2 = 6CO2 + 6H2O

MW of glucose = 180 g/mole
1 ppm = 1mg/l
glucose= 150ppm = 150mg/l
Therefore THOD = (6*32 g/mole O2 * 150 mg/L glucose) / 180 g/mole glucose = 160 mg/L