28 g of ${{N}*{2}}$ molecules contain 2 x 6-023 x ${{10}^{23}}$ atoms.
Hence, 1.4 g of ${{N}*{2}}$ molecules contain 2X6’°OQX1023 x 1.4 = 6.023 x ${{10}^{22}}$ atoms.

# Calculate the number of atoms present in 1.4 g of ${{N}_{2}}$ molecule

**prasanna**#1