Balance the following redox reaction by inserting the appropriate coefficients.
HNO3 + H2S ----> NO +S + H2O.
1). In H 2 S + HNO 3 -> NO +S + H 2 O
At first we will, consider for both the half reactions
Now, to balance no. of electrons in both the side we multiply eq.1 with 3 and eq. 2with 2and then add them to get the resultant balanced reaction as: