B$C{{l}_{3}}$ is planar but anhydrous Al$C{{l}_{3}}$ is tetrahedral. Explain

cbse
chemicalbonding

#1

B atom in B$C{{l}{3}}$ is sp2 hybridized due to which the shape of B$C{{l}{3}}$ is triangular planar. Anhydrous Al$C{{l}{3}}$ exists as dimer with the formula A${{l}{2}}$$C{{l}_{6}}$.