Assign oxidation number to the underlined elements in each of the following species

#1

Assign oxidation number to the underlined elements in each of the following species

#2

(a) Let the oxidation no. of P in Na\${{H}{2}}\$P\${{O}{4}}\$ be x.

• 1 + 2(+ 1) + x + 4(- 2) =0
• 1 + 2 + x-8 =0
x = + 5
Oxidation number of P in Na\${{H}{2}}\$P\${{O}{4}}\$ = + 5.
(b) Let the oxidation no. of S in NaHS\${{O}_{4}}\$ be x.
• 1 + 1 + x + 4(- 2) =0
• 2 + x - 8=0
x = + 6
Oxidation number of S in NaHS\${{O}{4}}\$ = + 6.
© Let the oxidation number of P in \${{H}
{4}}\$\${{P}{2}}\$\${{O}{7}}\$ be x.
4(+ 1) + 2x + 7(-2) =0
• 4 + 2x -14 =0
2x =10
x = + 5
Oxidation number of P in \${{H}{4}}\$\${{P}{2}}\$\${{O}{7}}\$ = + 5.
(d) Let the oxidation no. of Mn in \${{K}
{2}}\$Mn\${{O}_{4}}\$ be x.
2(+ 1) + x + 4(- 2) =0
• 2 + x-8 =0
x = + 6
Oxidation number of Mn in \${{K}{2}}\$Mn\${{O}{4}}\$ = + 6.
(e) Let the oxidation number of oxygen in Ca\${{O}_{2}}\$ be x.
• 2 + 2x =0
[oxidation no. of Ca = + 2]
2x = -2
x =-1
Oxidation number of O in Ca\${{O}{2}}\$ =-1.
(f) Let the oxidation no. of B in NaB\${{H}
{4}}\$ be x.
• l+x + 4(-l) =0
[•.• oxidation no. of H = -1]
x-3 =0
x = + 3
Oxidation number of B in NaB\${{H}{4}}\$ = + 3.
(g) Let the Oxidation no. of S in \${{H}
{2}}\$\${{S}{2}}\$\${{O}{7}}\$ be x.
2(+1)+ 2x + 7(-2) =0
• 2 + 2x -14 =0
2x =12
x = + 6
Oxidation number of S in \${{H}{2}}\$\${{S}{2}}\$\${{O}{7}}\$ = + 6.
(h) Let the oxidation no. of S in KAl(S\${{({{O}
{4}})}{2}}\$).24\${{H}{2}}\$O = x
• 1 + 3 + 2x + 8(- 2) + 24(+ 2) + 24(- 2) = 0
• 4 + 2x -16 = 0
[O. No. of K = 1,O. No. of Al = 3]
2x =12
x = +6
Oxidation number of S in KAl(S\${{({{O}{4}})}{2}}\$).24\${{H}_{2}}\$O=+6