**An iron ore was found to contain 92.0% pyrite (fool’s gold). Pyrite has the formula FeS2 and is 46.5% iron. How many grams of iron are there in 59.1 grams of iron ore?**

**Answer:**

To find the amount of pyrite you need to multiply the total mass of the ore by the percent that is pyrite.

59.1g * .92 = 54.372g

Multiply the grams of pyrite by the percent of pyrite that is iron to get the number of grams of iron in the ore.

54.372g * .465 = 25.28298g

Adjust for significant figures.

25.3g iron