An iron ore was found to contain 92.0% pyrite (fool's gold). Pyrite has the formula FeS2and is 46.5% iron

fes2-and-465-iron

#1

An iron ore was found to contain 92.0% pyrite (fool’s gold). Pyrite has the formula FeS2 and is 46.5% iron. How many grams of iron are there in 59.1 grams of iron ore?

Answer:

To find the amount of pyrite you need to multiply the total mass of the ore by the percent that is pyrite.
59.1g * .92 = 54.372g
Multiply the grams of pyrite by the percent of pyrite that is iron to get the number of grams of iron in the ore.
54.372g * .465 = 25.28298g
Adjust for significant figures.
25.3g iron