An ideal gas expands isothermally, performing 4.14 × 103 J of work in the process

ideal-gas
isothermally

#1

An ideal gas expands isothermally, performing 4.14 × 103 J of work in the process. Calculate the heat absorbed during this expansion.

Answer:

The first law of thermodynamics states:

$ Q + W = \Delta*U $
Work done on the system is defined as positive here.

For an ideal gas internal energy U is a function of temperature only, U = U(T) only. Since the change in temperature is zero, delta U is zero. Therefore,

$ Q = W = 4.14\times10^{3} Joules$