**An alternate method to prove the midpoint theorem of a triangle?**

**Answer:**

If you read carefully G is actually the centroid. It is given that M and N are midpionts of AC and BC and they intersect at G. BM and AN are the medians and they intersect at centroid. Also it is said that CG extended gives CL ,so CL is inevitably the other median as it passes through G and hence AL=LB