**An airplane on a runway accelerates at 4.0 meters/second2 for 28.0 seconds before takeoff. How far does the plane travel on the runway before takeoff?**

**Answer:**

there is a formula . s=ut+ 0.5a*t^2
s = distance travelled(to be found)
u= initial velocity =0
a= acceleration= 4
t=28 sec
put in the equation
u get s= 0*28 + 0.5

*4*(28)^2 = 0+ 1568 = 1568 m