An airplane is traveling at a fixed altitude with an outside wind factor. The airplane is headed N 40o W at a speed of 600 miles per hour. As a airplane comes to a certain point, it comes across a wind in the direction N 45o E with a velocity of 80 miles per hour. What are the resultant speed and direction of the airplane? Round your Answers to the nearest hundredth.
Split the two vectors in both x and y directions.
Assume that E=east is the positive direction, and W=west as the negative direction.
Result: (-460) + (57) = -403 or 403 West
Result: (386) + (57) = +443 or 443 North
Use Pythagorean Theorem to solve the resultant speed.
c=599 mi/hr <—Resultant Speed
Use Tangent in Trig to find direction.
or 47.7\textdegree West <—Direction
599mi/hr at 47.7\textdegree West