Aluminum oxide reacts with Nitric Acid to make aluminum nitrate and water. How much aluminum nitrate is made if you react 250 grains of aluminum oxide with 200 grams of nitric acid?
A. Balanced the equation:
B. What is the limiting reactant?
C. How many grams of aluminum nitrate are made
The Components are : Al2O3 + HNO3 -> Al(NO3)3 + H20.
Now we balance it: Al2O3 + 6 HNO3 -> 2 Al(NO3)3 + 3 H2O
We See that it takes 102 moles of Aluminum Oxide to react with 328 moles of Nitric Acid as we see in the equation. The Limiting Reagent is the Nitric Acid because we will run out of Acid before Oxide. It will take about 62.2 grams of aluminum to react with 200 grams of nitric oxide. That means that the total mass is 262.2 grams. The molar mass of 3 H2O is 54. 262.2 - 54 = 208.2 Grams of Aluminum Nitrate. We can do this because no mass is lost in the equation.