A watermelon seed has the following coordinate

coordinates

#1

A watermelon seed has the following coordinates: x = -5.6 m, y = 8.6 m, and z = 0 m. Find its position vector as (a) a magnitude and (b) an angle relative to the positive direction of the x axis. If the seed is moved to the xyz coordinates (1.8 m, 0 m, 0 m), what is its displacement as © a magnitude and (d) an angle relative to the positive direction of the x axis? Put the angles in the range (-180°, 180°

Answer:

Position vector of the seed: -5.6i+8.6j
Magnitude=10.26m
angle with the negative x axis= arctan(8.6/5.6)=56.9degrees
angle with positive x axis=180-56.9=123.1 degrees
Displacement=7.4i+8.6j
magnitude of displacement=11.35m
angle displaced 123.1degrees