**A train travels at 1.3 m/s^2. How long to reach a speed of 75km/h**

**Answer:**

Since the train started from rest initial velocity (u) =0 m/s

Acceleration (a) = 1.3 m/s^2

Final velocity (V) = 75km/h

(converting km/h to meter/sec or m/s)

=75*1000meter/3600sec (1km=1000mtrs,1hr=3600secs)

(v) =20.83m/s

Time(t) = ?

From the eq of kinematics,

V=u+at…(1)

substituting all the values of u,v,a,t in eq…(1)

20.83m/s = 0m/s + (1.3m/s^2)(t)

20.83m/s= (1.3m/s^2)(t)

(t)=(20.83)/(1.3)=16.025secs

–>It takes 16.025secs to reach the speed of 75km/h