**A total of $54,250 is to be invested, part at 5.370% annual interest and the rest at 6.720% annual interest. How much is invested at each rate to provide an annual interest income of $3,100?**

**Answer:**

This can must easily be solved as a system of equations

your first equation will be

x+y=54250

second is

.0537x+.0672y=3100

Use substitution

x=54250-y

Now plug this in the other equation

.0537(54250-y)+.0672y=3100

Solving for y you will find 13835.2

x will then be equal to 40414.82

You must round money to the hundredth place which is why the answer doesnâ€™t perfectly add up to 54250.