**A square plate has an area of 29.00 cm2 at 20.0C. It will be used in a low temperature experiment at T = 10.0K where it must have an area of 28.00 cm2. What area must be removed form the plate at 20.0C for it to have the correct area at 10.0 K? (The coefficient of linear expansion is 10 106 (C)1.)**

**Answer:**

basically linear expansion is given by formula

linear area expansion is approx.= Area (initial)*c*(change in temp)

where c is coeff of linear area expansion expansion

And

final area expression as A(final)=A(initial)+change in area

A(final)=A(initial)*(1+c*(Δ.T))

just substitute A(final) =28 cm^2

A(initial)=x(unknown)

coeff of linear expansion is given so double it up for area expansion coeff

enter "c’=20*10^-6

chnge in temp would be = for this convert 20 degree celsius to kelvin and take change w.r.t to 10 k

change in temp would be =22.8

using above information calculate A(initial)

report answer as =29 cm^2 - A(initial)

report answer is your answer…

your welcome