A science student riding on a flatcar of a train moving at a constant speed of 5.50 m/s throws a ball toward the caboose along a path that the student judges as making an initial angle of 60.0° with the horizontal. The teacher, who is standing on the ground nearby, observes the ball rising vertically. How high does the ball rise?
v cos60’=5.50 (where v=》velocity of projection)
velocity of projection=》11m/s
= v sin60’
=》v sin60’ is the vertical component and it is w.r.t ground.
=》Height of ball= v^2 sin^2 60’/2g (g=10m/s^2)
= 4.53m Answer