**A science student riding on a flatcar of a train moving at a constant speed of 5.50 m/s throws a ball toward the caboose along a path that the student judges as making an initial angle of 60.0° with the horizontal. The teacher, who is standing on the ground nearby, observes the ball rising vertically. How high does the ball rise?**

**Answer:**

V=5.50 m/s

v cos60’=5.50 (where v=》velocity of projection)

v×1/2=5.5

v=11m/s

velocity of projection=》11m/s

= v sin60’

=11×(3)^1/2/2 m/s

=》v sin60’ is the vertical component and it is w.r.t ground.

=》Height of ball= v^2 sin^2 60’/2g (g=10m/s^2)

= 121×3/4/2×10

= 12.1×3/2

=36.3/8 m

= 4.53m Answer