A science student riding on a flatcar of a train moving at a constant speed of 5.50 m/s throws a ball toward

constant-speed
initial-angle-60

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A science student riding on a flatcar of a train moving at a constant speed of 5.50 m/s throws a ball toward the caboose along a path that the student judges as making an initial angle of 60.0° with the horizontal. The teacher, who is standing on the ground nearby, observes the ball rising vertically. How high does the ball rise?

Answer:

V=5.50 m/s
v cos60’=5.50 (where v=》velocity of projection)
v×1/2=5.5
v=11m/s
velocity of projection=》11m/s
= v sin60’
=11×(3)^1/2/2 m/s
=》v sin60’ is the vertical component and it is w.r.t ground.
=》Height of ball= v^2 sin^2 60’/2g (g=10m/s^2)
= 121×3/4/2×10
= 12.1×3/2
=36.3/8 m
= 4.53m Answer