A projectile is fixed at an angle of 15° to the horizontal with the speed v. If another projectile is projected with the same speed, then at what angle with the horizontal it must be projected so as to have the same range ?

# A projectile is fixed at an angle of 15° to the horizontal with the speed v

**prasanna**#2

For same R and v, the sum of the two angle of projection is 90°. As one angle is of 15°, other, should be 90° -1,5° = 75°.