A pilot flew a jet form Montreal to Los Angeles a distance of 2500 miles. On the return trip the average speed was 30% faster

montreal-to-angeles

#1

A pilot flew a jet form Montreal to Los Angeles a distance of 2500 miles. On the return trip the average speed was 30% faster than the outbound speed the round trip took 9 hour and 10 min what was the speed from Montreal to las Angeles

Answer:

Let the outbound speed = x
return trip speed = x + 30x/100 = 13x/10
let t1 and t2 be the time taken to travel on way and return journey.
it is given that t1 + t2 = 9 hr 10 min = 9.167 hrs

time = distance/speed

t1 = 2500/x
t2=2500/13x/10 = 25000/13x

t1 + t2 = 9.167
2500/x + 25000/13x = 9.167
32500 + 25000 = 119.171 x
x = 57500/119.171
x = 482.5 miles/hr

speed from montreal to los angeles = 482.5 m/hr