A particle leaves the origin with an initial velocity of v-> = (7.92i) m/s and a constant of acceleration a-> = (-1.61i - 4.72j) m/s^2. When the particle reaches its maximum x coordinate, how far (in m) is it from the origin? The answer is 60.m. I’d like to know how you get that answer.
First, we have to find out how many seconds has to pass until the particle stopped moving in x direction. Notice that the initial velocity has only horizontal component meaning that it moves only in x direction, and (de)acceleration’s direction is completely opposite.
So, first we find t such that there is no more movement to the right in x direction.