A particle leaves the origin with an initial velocity of v-> = (7.92i) m/s and a constant of acceleration a-> = (-1.61i - 4.72j) m/s^2

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A particle leaves the origin with an initial velocity of v-> = (7.92i) m/s and a constant of acceleration a-> = (-1.61i - 4.72j) m/s^2. When the particle reaches its maximum x coordinate, how far (in m) is it from the origin? The answer is 60.m. I’d like to know how you get that answer.

Answer:

First, we have to find out how many seconds has to pass until the particle stopped moving in x direction. Notice that the initial velocity has only horizontal component meaning that it moves only in x direction, and (de)acceleration’s direction is completely opposite.

So, first we find t such that there is no more movement to the right in x direction.

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