A moderate wind accelerates a pebble over a horizontal xy plane with constant acceleration a=5m/(s^2)i + 7m/(s^2)j. AT time t=0 the velocity is 4.0 m/s. What is the velocity when it has been displaced 12m parallel to the x axis? found the answer, my question is why doesn’t the 4m/s starting velocity apply to the vertical motion as well?
Direction of initial velocity is not given, so we can assume that the direction is the same as the direction of wind.
Direction of the wind is: