A load of 102 kg is supported by a wire of length 2 m and cross-sectional area 0.1 cm2

cross-sectional
young’s-modulus

#1

A load of 102 kg is supported by a wire of length 2 m and cross-sectional area 0.1 cm2
. The wire is stretched by 0.22 cm. Find the tensile stress, tensile strain, and Young’s modulus

Answer:

Tensile Stress = F/A = mg/A = (100kg x 9.80m/s^2) / (0.10 x 10^-4 m^2) = 1.0 x 10^8 N/m^2
Tensile Strain = ΔL / L = (0.22 x 10^-2m) / 2.0m = 0.11 x 10^-2
Young’s modulus = stress/strain = (1.0 x 10^8 N/m^2) / (0.11 x 10^-2) = = 9.1 x 10^10 N/m^2