A horizontal force of 310 N is exerted on a 2.0-kg ball as it rotates uniformly in a horizontal circle of radius .90 m. Calculate the speed of the ball

horizontal-force

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A horizontal force of 310 N is exerted on a 2.0-kg ball as it rotates uniformly in a horizontal circle of radius .90 m. Calculate the speed of the ball.

Answer:

F = m.w^2.r
where,
F= force = 310 N
m = mass = 2 kg
r = 0.9 m
w = angular velocity in radians per second, speed of the ball can be calculated from w as v=w.r
Rearragning the force expression, we have
w^2 = F/mr = 172.22
So w = 13.12 and v= wr = 11.81 m/s