**A golf ball with an initial angle of 38° lands exactly 230 m down the range on a level course.**

**a. Neglecting air friction, what initial speed would achieve this result?**

**b. Using the speed determined in item (a), find the maximum height reached by the ball.**

**Answer:**

A)Range,R= v^2 sin2(θ)/g

230= v^2 sin (θ).cos (θ)/g

230= v^2×2 sin (38’).cos (38’)/g

230= v^2×2×0.615×0.78/10

230×10/2×0.615×0.78=v^2

2397.33=v^2

v= (2397.33)^1/2 m/s

B) maximum height

=v^2 sin^2 (θ)/2g

= 2397.33×0.378/2×10

= 906.19/2×10

= 45.31m Answer