A golf ball with an initial angle of 38° lands exactly 230 m down the range on a level course.
a. Neglecting air friction, what initial speed would achieve this result?
b. Using the speed determined in item (a), find the maximum height reached by the ball.
A)Range,R= v^2 sin2(θ)/g
230= v^2 sin (θ).cos (θ)/g
230= v^2×2 sin (38’).cos (38’)/g
v= (2397.33)^1/2 m/s
B) maximum height
=v^2 sin^2 (θ)/2g
= 45.31m Answer