**A force F with arrow applied to an object of mass m1 produces an acceleration of 3.40 m/s2. The same force applied to a second object of mass m2 produces an acceleration of 1.40 m/s2.
(a) What is the value of the ratio m1/m2?**

**(b) If m1 and m2 are combined into one object, find its acceleration under the action of the force F with arrow.**

**m/s2**

**Answer:**

a)F1=m1*a1=m1*3.40

F2=m2*a2=m2*1.40

same force is acted on m1 and m2

m1*3.40=m2*1.40

m1/m2=1.40/3.40

m1/m2=7/17

it means m1=7kg, m2=17kg

b)Force acted on m1 F=7*3.40=23.8 kg m/s^2
m1+m2=7+17=24 kgs.
F=ma
23.8=24*a

a=23.8/24

a=0.9916 m/s^2