(a) Draw a picture of a triangle with two sides a and b. Write down a formula for the
height of the triangle in terms of the crossproduct, and deduce a formula for the area of the triangle.
(b) Find the area of a triangle with corners P(0,1,0), Q(1,2,−1), R(2,2,2).
height of triangle = Area of parallelogram / base of parallelogram = a x b / [a]
Coordinate vectors; PQ=(1,1,-1) PR=(2,1,2) let a = PQ and b = PR
a x b = ( a2b3-a3b2 , a3b1-a1b3 , a1b2-a2b1)
area of triangle = 1/2 * [a x b] = 0.5 x (3^2 + -4^2 + 1^2)^0.5 = 2.55