A diamond breaks into 3 piece weighing in the ratio 2:3:5.The value of the diamond is proportionate to the square of it’s weight.If the value of original is Rs 20000,find loss due to breakage
Let’s say the original was 10 carats, the pieces would be 2 carats, 3 carats and 5 carats, which add to 10. (notice that 10 was chosen specifically because it was the sum of 2+3+5)
“proportionate to the square of it’s weight” for the original is an equation like
V=kw², where k is a constant, w is weight and V is value.
To determine k, we substitute the known values for the unbroken diamond
So, the equation now becomes V=200w²
Now we substitute the weights of the piece and add up each value.
Adding the values gives you
So, the loss from the breakage is 20,000-7600=12,400
Notice that the value of a bog diamond is greater than a few smaller diamonds the total the same weight. This makes sense, really big diamonds are rare.