A craftsman and his apprentice working together can complete a project in 4 days. If each works on the project individually, the apprentice would have taken 6 days more than the craftsman. How long would it take for the apprentice to do the job alone?
If craftsman alone can complete the job in ‘x’ days, then apprentice alone will take x+6 days to complete the job.
As 1 day work of craftsman and apprentice=1/4, So (1/x)+[1/(x+6)] =1/4
(x+6+x)/ [x(x+6)] =1/4
x^2 - 2x -24=0
So apprentice alone will take x+6 =6+6=12 days to complete the job.