A constant electric field of 250 n/c is between a set of parallel plates that have a potential difference between them of 12.0 V. How far apart are the plates?

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#1

A constant electric field of 250 n/c is between a set of parallel plates that have a potential difference between them of 12.0 V. How far apart are the plates?

Answer:

Since the field is uniform, the potential difference is the product of the field intensity by the distance between the plates:

V = E.d

d = V/E

d = (12 V)/(250 N/C) = 0.048 m = 48 mm

Note: V = N m/C

d=E/V=250/12 m