A certain substance has a heat of vaporization of 42.18 kJ/mol. At what Kelvin temperature will the vapor pressure be 5.50 times higher than it was at 351 K?

heat-of-vaporization
kelvin-temperature

#1

A certain substance has a heat of vaporization of 42.18 kJ/mol. At what Kelvin temperature will the vapor pressure be 5.50 times higher than it was at 351 K?

Answer:

Let:

P1=initial pressureP2=final pressureT1=initial temperatureT2=final temperatureΔH=heat of vaporization

We are going to use Clausius-Clapeyron Equation:
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