**A certain substance has a heat of vaporization of 42.18 kJ/mol. At what Kelvin temperature will the vapor pressure be 5.50 times higher than it was at 351 K?**

**Answer:**

Let:

P1=initial pressureP2=final pressureT1=initial temperatureT2=final temperatureΔH=heat of vaporization

We are going to use Clausius-Clapeyron Equation: