**A car travels 1.5 km in the x-direction, then turns left 58.9◦ to the original direction and travels an additional distance of 3.04 km.Calculate the x component of the car’s net**

**displacement.**

**Answer:**

X direction component of 58,9 turn is 3,04*cos (58,9) \
That is 3,04*0,5165= 1,57. \

So, final answar is 1,57+1,5 = 3,07 km car travels in x-direction.