**A car traveling at 50 ft/sec decelerates at a constant 8 feet per second per second. How many feet does the car travel before coming to a complete stop?**

**Answer:**

Using the first equation of motion

v=u+a*t

u=50

a=-8

v=0 (Complete stop)

therefore,

t=( v - u ) / a

t= (0 - (-50) ) / (-8)

t=6.25 second

Now,

Using second equation of motion,

s=u*t +1/2*a*t^2

s=50*(6.25) + 1/2*(-8)*((6.25^2)

s=312.5 -156.25

answer= 156.25 feet