A car traveling at 50 ft/sec decelerates at a constant 8 feet per second per second. How many feet does the car travel before coming to a complete stop?
Using the first equation of motion
v=0 (Complete stop)
t=( v - u ) / a
t= (0 - (-50) ) / (-8)
Using second equation of motion,
s=50*(6.25) + 1/2*(-8)*((6.25^2)
answer= 156.25 feet