A car starts from rest and speeds up at a constant rate of 2.01 m/s^2 as it moves around a circular track

constant-rate

#1

A car starts from rest and speeds up at a constant rate of 2.01 m/s^2 as it moves around a circular track. Find the magnitude of the car’s acceleration (in m/s^2) at the instant when it completes the first revolution. The answer is 25.3 m/s^2. Please tell me how to solve this thanks.

Answer:

you are given the tangential acceleration

to find the centripetal acceleration, you need the track size

the acceleration is the vector sum of tangential and centripetal