**A car passes a crossing and 10 seconds later a police car passes the crossing in pursuit.Both cars have constant speed how far from the crossing will the police car catch the speeding car?**

**Answer:**

With the 10 second lead the speeding car will be 200 m ahead of the police officer so to find when the officer catches the speeding car we can take 200 m = (10 m/s) (t) using 10 because this is the difference in the speed of the cars and thus amount the the officer gains on the speeder each second. So in 20 seconds the police car will catch the speeding car.