a block has an intial speed of 6.0m/s up an inclined plane that makes an angle of 37 degrees with the horizontal. Ignoring friction, what is the blocks speed after it has traveled 2.0m?
ha idk if i did it right. but oh well i tried to help!
first, use cos and sin to find initial velocity in x and y direction.
- cos37 = Vi (x) / 6 and same goes for sin37
next, you calculate the time using Vf = Vi + a (t)
- 0 m/s^2 = (sin37 = Vi (y) / 6) + (-9.8 m/s^2) t
t = 0.37 seconds
third, you find the initial velocity (block’s speed after it traveled 2 m) using x = Vi (t) + 1/2 (a) t
2.0m = Vi * 0.37 m/s + 0 (bc theres no acceleration in the horizontal direction)
In conclusion, the block’s speed will be 5.41 m/s after it traveled 2.0 meters.