A basketball has a mass of 577 g. Moving to the right and heading downward at an angle of 28° to the vertical,

momentum-charge

#1

A basketball has a mass of 577 g. Moving to the right and heading downward at an angle of 28° to the vertical, it hits the floor with a speed of 4 m/s and bounces up with nearly the same speed, again moving to the right at an angle of 28° to the vertical. What was the momentum change Δp?
(Take the +x axis to be to the right and the +y axis to be up. Express your answer in vector form.)

Answer:

Mass (M) = 0.577 kg
Velocity before hitting the floor (u) = 4sin(28) x + (-4)cos(28) y
Velocity after hitting the floor (v) = 4
sin(28) x + 4
cos(28) y
Change in velocity (Δv) = v-u = 0 x + 8cos(28) y
Change in momentum (Δp) = M
Δv
Δp = 0.5778cos(28) y
Δp = 4.075 kg*m/s y (in upward direction only)