A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function h = -16t^2 + 48t + 6

maximum-height
upward-velocity

#1

A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function h = -16t^2 + 48t + 6 . In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?

Answer:

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First coordinate of the vertex represents the time at which maximum is achieved and second coordinate represents the actual height.

In conclusion, the ball will reach its maximum height in 1.5 second and the ball’s maximum height is 30 feet.