**A 548 g ball strikes a wall at 13.5 m/s and rebounds at 14.3 m/s. The ball is in contact with the wall for 0.031 s.**

**Answer:**

The impulse F(t2 – t1) is equal to the variation of the amount of linear movement m(V2 – V1)

That is: F(t2 – t1) = m(V2 – V1),

Where: (t2 - t1) = 0.031 s and the mass is m = 0.548 kg

Solving and substituting:

F = m(V2 – V1)/ (t2 – t1) = 0,548(14,3 – 13,5)/0,031

F = 14.14 N