A 548 g ball strikes a wall at 13.5 m/s and rebounds at 14.3 m/s. The ball is in contact with the wall for 0.031 s

strikes-wall-rebound

#1

A 548 g ball strikes a wall at 13.5 m/s and rebounds at 14.3 m/s. The ball is in contact with the wall for 0.031 s.

Answer:

The impulse F(t2 – t1) is equal to the variation of the amount of linear movement m(V2 – V1)
That is: F(t2 – t1) = m(V2 – V1),
Where: (t2 - t1) = 0.031 s and the mass is m = 0.548 kg
Solving and substituting:
F = m(V2 – V1)/ (t2 – t1) = 0,548(14,3 – 13,5)/0,031
F = 14.14 N