A 50 kg girl wearing high heels, shoes balances on a single heel. The heel is circular with a diameter 1.0 cm. What is the pressure exerted on the horizontal floor?
Given, mass of girl (m) = 50 kg
Diameter of circular heel (2 r) = 1.0 cm
Radius ® = 0.5 cm = 5x${{10}^{-3}}$ m
Area of circular heel (A) = $\pi$${{r}^{2}}$
= 3.14 x ( 5 x ${{10}^{-3}}$ ) 5x${{10}^{-3}}$ ${{m}^{2}}$
= 78.50 x ${{10}^{-6}}$ ${{m}^{2}}$
Pressure exerted on the horizontal floor p = F/A
= mg/A =50 x 9.8 /78.50 x ${{10}^{-6}}$ ${{m}^{2}}$ = 6.24 x ${{10}^{6}}$ Pa